Exercise


ABy Admin
Nov 19'23

Answer

Solution: D.

[[math]] \begin{aligned} & P(0, m)=(1+i)^{-m} \\ & P(0, n)=(1+i)^{-n} \\ & X=\frac{(1+i)^{-m}}{(1+i)^{-n}}=(1+i)^{-m+n} \\ & X=\frac{P(0, m)}{P(0, n)}\end{aligned} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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