Exercise
ABy Admin
Jan 20'24
Answer
Answer: D
[math]\pi=\frac{1000{ }_{10} \mid \ddot{a}_{55}}{\ddot{a}_{55: \overline{10}}-(I A)_{55: \overline{10}}^{1}}=\frac{1000(0.59342)(13.5498)}{8.0192-0.14743}=1021.46[/math]
[math]{ }_{9} V=1000 \quad{ }_{1} \mid \ddot{a}_{64}+10 \pi A_{64: 1}^{1}-\pi \ddot{a}_{64: 1}[/math]
[math]=1000 \frac{1}{1.05}\left(\frac{94,579.7}{95,082.5}\right) 13.5498+10(1021.46) \frac{1}{1.05}(0.005288)-1021.46[/math]
[math]=11,866[/math]