Exercise
ABy Admin
Nov 18'23
Answer
Solution: A
[[math]]
\begin{aligned}
& {\left[100 \ddot{s}_{\overline{5} \mid 0.13}+50 \ddot{s}_{\overline{3} | 0.13}\right](1.13)^5=1703.81} \\
& \frac{x}{1.12^{1 / 2}-1}=1703.81 \\
& X=99.33
\end{aligned}
[[/math]]