Exercise
May 13'23
Answer
Key: C
[[math]]
\operatorname{E}(X \wedge x) = \frac{\theta}{\alpha -1} \left [ 1-\left( \frac{\theta}{x+\theta}\right)^{\alpha-1}\right] - \frac{2000}{1} \left [ 1-\frac{2000}{x + 2000}\right ] = \frac{2000x}{x + 2000}
[[/math]]
[math]x[/math] | [math]\operatorname{E}(X \wedge x)[/math] |
---|---|
[math]\infty[/math] | 2000 |
250 | 222 |
2250 | 1059 |
5100 | 1437 |
[[math]]
\begin{aligned}
&0.75[ \operatorname{E}[ X \wedge 2250) − \operatorname{E}[ X \wedge 250)] + 0.95 [ \operatorname{E}[ X ) − \operatorname{E}[ X \wedge 5100)] \\
&0.75(1059 − 222) + 0.95(2000 − 1437) = 1162.6\\
\end{aligned}
[[/math]]
The 5100 breakpoint was determined by when the insured’s share reaches 3600: 3600 = 250 + 0.25 (2250 – 250) + (5100 – 2250)