Exercise
May 07'23
Answer
Solution: C
The number of defective modems is 20% x 30 + 8% x 50 = 10.
The probability that exactly two of a random sample of five are defective is
[[math]]
\frac{\binom{10}{2} \binom{70}{3}}{\binom{80}{5}} = 0.102.
[[/math]]