Exercise
ABy Admin
May 04'23
Answer
Solution: E
From the Law of Total Probability, the required probability is
[[math]]
\begin{align*}
\sum_{k=0}^{\infty} P(\textrm{0 accidents with an insured driver} | \textrm{k accidents})P( \textrm{k accidents})
&= \sum_{k=0}^{\infty} (0.75)^k \frac{e^{-5}5^k}{k!} \\ &= \frac{e^{-5}}{e^{-3.75}} \sum_{k=0}^{\infty} \frac{e^{-3.75}(3.75)^k}{k!} \\
&= e^{-1.25} \\
&= 0.287.
\end{align*}
[[/math]]