Exercise


ABy Admin
May 04'23

Answer

Solution: E

From the Law of Total Probability, the required probability is

[[math]] \begin{align*} \sum_{k=0}^{\infty} P(\textrm{0 accidents with an insured driver} | \textrm{k accidents})P( \textrm{k accidents}) &= \sum_{k=0}^{\infty} (0.75)^k \frac{e^{-5}5^k}{k!} \\ &= \frac{e^{-5}}{e^{-3.75}} \sum_{k=0}^{\infty} \frac{e^{-3.75}(3.75)^k}{k!} \\ &= e^{-1.25} \\ &= 0.287. \end{align*} [[/math]]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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