Exercise
ABy Admin
Nov 18'23
Answer
Solution: C
[[math]]
\begin{array}{l}{{50,000\bigg[\frac{(1+i)^{30}-(1.03)^{30}}{(1+i)^{30}(i-0.03)}\bigg](1+i)=5,000\bigg[\frac{{(1+i)}^{30}-{(1.03)}^{30}}{i-0.03}\bigg]}}\\ {{50,000/(1+i)^{29}=5,000}} \\ {{(1+i)^{29} = 10}} \\i = 10^{1/29} -1 = 0.082637 \end{array}
[[/math]]
The accumulated amount is
[[math]]
50.000\bigg[\frac{(1.082637)^{30}-(1.03)^{30}}{(1.082637)^{30}(0.082637-0.03)}\bigg](1.082637)=797.836.82
[[/math]]