Exercise
Answer
Solution: C
Note that 6 years [math]=6 \times 12[/math] months [math]=72[/math] months; 4 years [math]=48[/math] months; 2 years [math]=24[/math] months.
After 6 years, the first two years of payments have grown to [math]50 \ddot{s}_{\overline{24} \mid j}(1+i)^4[/math]. After 6 years, the next two years of payments have grown to [math]100 \ddot{s}_{\overline{24} \mid j}(1+i)^2[/math]. After 6 years, the last two years of payments have grown to [math]150 \ddot{s}_{\overline{24} \mid j}(1+i)^0[/math]. Let [math]T[/math] be the total after 6 years. Then the total after 7 years is [math]T(1+i)[/math]. Thus
Divide by 50 and factor to get
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.