Exercise
ABy Admin
Nov 18'23
Answer
Solution: D
For the first perpetuity,
[[math]]
\begin{align*}
\frac{1}{\left(1+\dot{l}\right)^{2}-1}+1 &= 7.21 \\
\frac{1}{6.21} &= \left(1+i\right)^{2}-1 \\
i &= 0.0775
\end{align*}
[[/math]]
For the second perpetuity,
[[math]]
\begin{align*}
R\left[\frac{1}{\left(1.0775+0.01\right)^{3}-1}+1\right]\left(1.0875\right)^{-1}=7.21 \\
1.286139 R = 7.21(1.0875) 0.286139\\
R=1.74
\end{align*}
[[/math]]