Exercise


ABy Admin
Nov 18'23

Answer

Solution: B

For the first perpetuity,

[[math]] \begin{align*} 32 &=10\left( v^{3}+ v^{6}+\cdot\cdot\cdot\right)=10 v^{3}/\left(1- v^{3}\right)\\ 32-32 v^{3} &=10 v^{3} \\ v^{3} &=32/42. \end{align*} [[/math]]

For the second perpetuity

[[math]] X= v^{13}+ v^{23}+\cdots= v^{1/3}\,/\,(1- v^{1/3})=(32\,/\,42)^{1/9}\,/\,[1-(32\,/\,42)^{1/9}\,]=32.599. [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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