Exercise


ABy Admin
Nov 19'23

Answer

Solution: B

Let X be the price of Bond X. Then, for the two bonds:

[[math]] \begin{array}{l}{{X=10,000(0.03)a_{\overline{{{2n}}}|0.035}+c(1.035)^{-2n}}}\\ {{X-969.52=10,000(0.025)a_{\overline{{{2n}}}|0.035}+(c+50)(1.035)^{-2n}}}\end{array} [[/math]]

Subtracting the second equation from the first gives

[[math]] \begin{array}{l}{{969.52=50a_{\overline{{{2n}}}|0.035}-50(1.035)^{-2n}}}\\ {{969.52=\frac{50}{0.035}[1-(1.035)^{-2n}]-50(1.035)^{-2n}}}\\ {{1.035^{-2n}=459.05/1478.57=0.310469}}\\ {{m=-(0.5)\ln(0.310469)/\vert\ln(1.035)=17.}} \end{array} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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