Exercise
ABy Admin
Apr 29'23
Answer
Solution: A
Let B be the event that the policyholder has high blood pressure and C be the event that the policyholder has high cholesterol. We are given [math]\operatorname{P}(B) = 0.2, \operatorname{P}(C) = 0.3,[/math] and [math]\operatorname{P}(C | B) = 0.25 [/math]. Then,
[[math]]
\operatorname{P}(B | C) = \frac{\operatorname{P}(B \cap C)}{\operatorname{P}(C)} = \frac{\operatorname{P}(C |B) \operatorname{P}(B) }{\operatorname{P}(C)} = \frac{0.25(0.2)}{0.3} = 1/6.
[[/math]]