Exercise
ABy Admin
Nov 18'23
Answer
Solution: D
The given information yields the following amounts of interest paid:
Seth = 5000 ((1+0.12/2)10-1)= 8954.24- 5000 = 3954.24
Janice = 5000(0.06)(10) = 3000.00
Lori = [math]P(10)[/math] - 5000 = 1793.40 where [math]P = \frac{5000}{a_{\overline{10}|6\%}}[/math] = 679.35
The sum is 8747.64.