Exercise
Apr 30'23
Answer
Solution: B
The state will receive 800,000($1) = $800,000 in revenue, and will lose money if there are 2 or more winning tickets sold. The player’s entry can be viewed as fixed. The probability the lottery randomly selects those same six numbers is from a hypergeometric distribution and is
[[math]]
\frac{\binom{6}{6} \binom{24}{0}}{\binom{30}{6}} = \frac{1(1)}{\frac{30!}{6!24!}} = \frac{6(5)(4)(3)(2)(1)}{30(29)(28)(27)(26)(25)} = \frac{1}{593775}
[[/math]]
The number of winners has a binomial distribution with n = 800,000 and p = 1/593,775. The desired probability is
[[math]]
\begin{align*}
\operatorname{P}(\textrm{2 or more winners}) &= 1 − \operatorname{P}(\textrm{0 winners}) − \operatorname{P}(\textrm{1 winner}) \\
&= 1 - \binom{800000}{0} \binom{1}{593775}^0 \binom{593774}{593775}^{800000} - \binom{800000}{1}\binom{1}{593775}^{700000} \\
&=1 − 0.2599 − 0.3502 =0.39.
\end{align*}
[[/math]]