Exercise


ABy Admin
Nov 18'23

Answer

Solution: D

[[math]] \begin{aligned} & F V=100\left[\frac{1-\left(\frac{0.9}{1.03}\right)^{20}}{0.03+0.10}\right](1.03)^{20} \\ & F V=1295.80 \end{aligned} [[/math]]

Alternatively,

[[math]] F V=100\left[(1.03)^{19}+0.9(1.03)^{18}+\cdots+(0.9)^{19}(1.03)^0\right]=100 \frac{(1.03)^{19}-(0.9)^{20}(1.03)^{-1}}{1-0.9(1.03)^{-1}}=1295.80 [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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