Exercise
ABy Admin
Nov 18'23
Answer
Solution: D
[[math]]
\begin{aligned}
& F V=100\left[\frac{1-\left(\frac{0.9}{1.03}\right)^{20}}{0.03+0.10}\right](1.03)^{20} \\
& F V=1295.80
\end{aligned}
[[/math]]
Alternatively,
[[math]]
F V=100\left[(1.03)^{19}+0.9(1.03)^{18}+\cdots+(0.9)^{19}(1.03)^0\right]=100 \frac{(1.03)^{19}-(0.9)^{20}(1.03)^{-1}}{1-0.9(1.03)^{-1}}=1295.80
[[/math]]