Exercise
ABy Admin
Nov 19'23
Answer
Solution: A
The book value after the third coupon is
[[math]]
7500(0.037)a_{\overline{{{37}}}|0.0265}+C(1.0265)^{-37}=6493.05+0.379943C
[[/math]]
and after the fourth coupon it is
[[math]]
7500(0.037)a_{\overline{300}|0.0265}+C(1.0265)^{-36}=6387.61+0.390012C.
[[/math]]
Then
[[math]]
\begin{array}{l}\\ {{6493.05+0.379943C-(6387.61+0.390012C)=28.31}}\\ {{105.44-0.01069C=28.31}}\\
{{C = 7660.15.}}
\end{array}
[[/math]]