Exercise
May 14'23
Answer
Key: B
[[math]]
\begin{aligned}
&R_{BF} = (1- \frac{1}{F}) R_{LR} + \frac{1}{f}R_{CL} \\
& 400,000 = (1-\frac{1}{f})250,000 + \frac{1}{f} 437,500 \Rightarrow f = 1.25 = \prod_{j=3}^{\infty} f_j \\
&1,120, 000 = (1- \frac{1}{f})1,200,000 + \frac{1}{f} 1,050,000 \Rightarrow f = 1.875 = \prod_{j=2}^{\infty} f_j \\
&f_2 = \frac{1.875}{1.25} = 1.5.
\end{aligned}
[[/math]]