Exercise


Nov 20'23

Answer

Solution: C

[[math]] {D}_{\mathrm{mod}}=-\frac{\frac{d}{d i}(1+i)^{-n}}{(1+i)^{-n}}=\frac{n(1+i)^{-n-1}}{\displaystyle{(1+i)^{-n}}}=n(1+i)^{-1} [[/math]]

Copyright 2023 . The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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