BBy Bot
Jun 09'24
Exercise
[math]
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}[/math]
Prove that if [math]A[/math] and [math]B[/math] are independent so are
- [math]A[/math] and [math]\tilde B[/math].
- [math]\tilde A[/math] and [math]\tilde B[/math].