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| rev | Admin | (Created page with "'''Answer: A''' <math>E[Z]=2 \cdot A_{40}-{ }_{20} E_{40} A_{60}=(2)(0.36987)-(0.51276)(0.62567)=0.41892</math> <math>E\left[Z^{2}\right]=0.24954</math> which is given in the problem. <math>\operatorname{Var}(Z)=E\left[Z^{2}\right]-(E[Z])^{2}=0.24954-0.41892^{2}=0.07405</math> <math>S D(Z)=\sqrt{0.07405}=0.27212</math> An alternative way to obtain the mean is <math>E[Z]=2 A_{40: 20 \mid}^{1}+{ }_{20 \mid} A_{40}</math>. Had the problem asked for the evaluation of th...") | Jan 18'24 at 11:27 | +694 |