Exercise
May 14'23
Answer
Key: C
Limited expected value =
[[math]]
\begin{aligned}
&\int_{0}^{1000}[1 − F ( x)]dx = \int_{0}^{1000} 0.8e^{-0.02x} + 0.2e^{-0.001x}dx \\
&= -40e^{-0.02x} - 200e^{-0.001x} \Big |_0^{1000} \\
&= −0 − 73.576 + 40 + 200 \\
&= 166.424
\end{aligned}
[[/math]]