Exercise
Answer
Solution: A
Let [math]a, b[/math], and [math]c[/math] represent the face values of the three bonds. One, two, three, and four years from now, respectively: the 1-year bond provides payments of [math]1.01 a, 0,0,0[/math]; the 3-year bond provides payments of [math]0.05 \mathrm{~b}, 0.05 \mathrm{~b}, 1.05 \mathrm{~b}, 0[/math]; and the 4-year bond provides payments of [math]0.07 c, 0.07 c, 0.07 c, 1.07 c[/math]. The total payments one, two, three, and four years from now must match the liabilities. Therefore, we have
Note that to find [math]X[/math], we do not need the first equation.
Solving the fourth equation for [math]c[/math] yields [math]c=\frac{7811}{1.07}=7300[/math].
Substituting this value of [math]c[/math] into the third equation and solving for [math]b[/math] yields
Finally, substituting these values of [math]b[/math] and [math]c[/math] into the second equation yields [math]X=0.05(14200)+0.07(7300)=1221[/math]