excans:B4a44e0a2b

Exercise

Jan 15'24

Answer

Answer: D

This is a mixed distribution for the population, since the vaccine will apply to all once available.

Available?

[math](A)[/math]	[math]\operatorname{Pr}(A)[/math]	[math]{ }_{2} p \mid A[/math]	[math]E(S \mid A)[/math]	[math]\operatorname{Var}(S \mid A)[/math]	[math]E\left(S^{2} \mid A\right)[/math]
Yes	0.2	0.9702	97,020	2,891	[math]9,412,883,291[/math]
No	0.8	0.9604	96,040	3,803	[math]9,223,685,403[/math]
			[math]E(S)[/math]		[math]E\left(S^{2}\right)[/math]
			96,236		[math]9,261,524,981[/math]
		[math]\operatorname{Var}(S)[/math]	157,285
		[math]S D(S)[/math]	397

As an example, the formulas for the "No" row are

[math]\operatorname{Pr}(\mathrm{No})=1-0.2=0.8[/math]

[math]{ }_{2} p[/math] given [math]\mathrm{No}=(0.98[/math] during year 1[math])(0.98[/math] during year 2[math])=0.9604[/math]

[math]E(S \mid \mathrm{No}), \operatorname{Var}(S \mid[/math] No [math])[/math] and [math]E\left(S^{2} \mid\right.[/math] No [math])[/math] are just binomial, [math]n=100,000 ; \mathrm{p}([/math] success [math])=0.9604[/math]

[math]E(S), E\left(S^{2}\right)[/math] are weighted averages,

[math]\operatorname{Var}(S)=E\left(S^{2}\right)-E(S)^{2}[/math]

Or, by the conditional variance formula:

[[math]] \begin{aligned} \operatorname{Var}(S) & =\operatorname{Var}[E(S \mid A)]+E[\operatorname{Var}(S \mid A)] \\ & =0.2(0.8)(97,020-96,040)^{2}+0.2(2,891)+0.8(3,803) \\ & =153,664+3,621=157,285 \\ \operatorname{StdDev}(S) & =397 \end{aligned} [[/math]]