⧼exchistory⧽
To view all exercises, please subscribe to guide
37 exercise(s) shown, 16 hidden
May 05'23

Let [math]X[/math] and [math]Y[/math] be continuous random variables with joint density function

[[math]] f(x,y) = \begin{cases} 24xy, \,\, 0 \lt x \lt 1 \,\, \textrm{and} \,\, 0 \lt y \lt 1-x \\ 0, \, \textrm{Otherwise.} \end{cases} [[/math]]

Calculate [math] \operatorname{P}[Y \lt X | X = 1/3][/math]

  • 1/27
  • 2/27
  • 1/4
  • 1/3
  • 4/9

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 05'23

Once a fire is reported to a fire insurance company, the company makes an initial estimate, [math]X[/math], of the amount it will pay to the claimant for the fire loss. When the claim is finally settled, the company pays an amount, [math]Y[/math], to the claimant. The company has determined that [math]X[/math] and [math]Y[/math] have the joint density function

[[math]] f(x,y) = \begin{cases} \frac{2}{x^2(x-1)}y^{-(2x-1)/(x-1)}, \,\, x \gt1, y \gt 1 \\ 0, \, \textrm{Otherwise.} \end{cases} [[/math]]

Given that the initial claim estimated by the company is 2, calculate the probability that the final settlement amount is between 1 and 3.

  • 1/9
  • 2/9
  • 1/3
  • 2/3
  • 8/9

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 05'23

An actuary determines that the annual number of tornadoes in counties P and Q are jointly distributed as follows:

Q= 0 Q=1 Q=2 Q=3
P=0 0.12 0.06 0.05 0.02
P=1 0.13 0.15 0.12 0.03
P=2 0.05 0.15 0.10 0.02

Calculate the conditional variance of the annual number of tornadoes in county Q, given that there are no tornadoes in county P.

  • 0.51
  • 0.84
  • 0.88
  • 0.99
  • 1.76

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 05'23

You are given the following information about [math]N[/math], the annual number of claims for a randomly selected insured:

[[math]] \operatorname{P}[N = 0] = \frac{1}{2}, \, \operatorname{P}[N = 1] = \frac{1}{3}, \, \operatorname{P}[N \gt1] = \frac{1}{6} [[/math]]

Let [math]S[/math] denote the total annual claim amount for an insured. When [math]N = 1 [/math], [math]S[/math] is exponentially distributed with mean 5. When [math]N \gt 1 [/math], [math]S[/math] is exponentially distributed with mean 8.

Calculate [math]\operatorname{P}(4 \lt S \lt 8) [/math]

  • 0.04
  • 0.08
  • 0.12
  • 0.24
  • 0.25

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 06'23

A fair die is rolled repeatedly. Let [math]X[/math] be the number of rolls needed to obtain a 5 and [math]Y[/math] the number of rolls needed to obtain a 6.

Calculate [math]\operatorname{E}(X | Y = 2). [/math]

  • 5.0
  • 5.2
  • 6.0
  • 6.6
  • 6.8

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 06'23

New dental and medical plan options will be offered to state employees next year. An actuary uses the following density function to model the joint distribution of the proportion [math]X[/math] of state employees who will choose Dental Option 1 and the proportion [math]Y[/math] who will choose Medical Option 1 under the new plan options:

[[math]] f(x,y) = \begin{cases} 0.50, \,\, 0 \lt x \lt 0.5, 0 \lt y \lt 0.5 \\ 1.25, \,\, 0 \lt x \lt 0.5, 0.5 \lt y \lt 1 \\ 1.50, \,\, 0.5 \lt x \lt 1, 0 \lt y \lt 0.5 \\ 0.75, \,\, 0.5 \lt x \lt 1, 0.5 \lt y \lt 1 \\ \end{cases} [[/math]]

Calculate [math]\operatorname{Var} (Y | X = 0.75)[/math].

  • 0.000
  • 0.061
  • 0.076
  • 0.083
  • 0.141

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 06'23

A company offers a basic life insurance policy to its employees, as well as a supplemental life insurance policy. To purchase the supplemental policy, an employee must first purchase the basic policy. Let [math]X[/math] denote the proportion of employees who purchase the basic policy, and [math]Y[/math] the proportion of employees who purchase the supplemental policy. Let [math]X[/math] and [math]Y[/math] have the joint density function [math]f(x,y) = 2(x+y)[/math] on the region where the density is positive.

Given that 10% of the employees buy the basic policy, calculate the probability that fewer than 5% buy the supplemental policy.

  • 0.010
  • 0.013
  • 0.108
  • 0.417
  • 0.500

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 06'23

Let [math]N[/math] denote the number of accidents occurring during one month on the northbound side of a highway and let [math]S[/math] denote the number occurring on the southbound side. Suppose that [math]N[/math] and [math]S[/math] are jointly distributed as indicated in the table.

N\S 0 1 2 3 or more
0 0.04 0.06 0.10 0.04
1 0.10 0.18 0.08 0.03
2 0.12 0.06 0.05 0.02
3 or more 0.05 0.04 0.02 0.01

Calculate [math]\operatorname{Var}(N | N + S = 2) [/math].

  • 0.48
  • 0.55
  • 0.67
  • 0.91
  • 1.25

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 07'23

A diagnostic test for the presence of a disease has two possible outcomes: 1 for disease present and 0 for disease not present. Let [math]X[/math] denote the disease state (0 or 1) of a patient, and let [math]Y[/math] denote the outcome of the diagnostic test. The joint probability function of [math]X[/math] and [math]Y[/math] is given by:

[[math]] \begin{align*} \operatorname{P}[X = 0, Y = 0] &= 0.800 \\ \operatorname{P}[X = 1, Y = 0] &= 0.050 \\ \operatorname{P}[X = 0, Y = 1] &= 0.025 \\ \operatorname{P}[X = 1, Y = 1] &= 0.125 \\ \end{align*} [[/math]]

Calculate [math]\operatorname{Var}(Y | X = 1) .[/math]

  • 0.13
  • 0.15
  • 0.20
  • 0.51
  • 0.71

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

May 07'23

An insurance policy is written to cover a loss [math]X[/math] where [math]X[/math] has density function

[[math]] f(x) = \begin{cases} \frac{3}{8}x^2, \, 0 \leq x \leq 2 \\ 0, \, \textrm{Otherwise.} \end{cases} [[/math]]

The time (in hours) to process a claim of size [math]x[/math], where [math]0\lt x \lt 2[/math] , is uniformly distributed on the interval from [math]x[/math] to [math]2x[/math].

Calculate the probability that a randomly chosen claim on this policy is processed in three hours or more.

  • 0.17
  • 0.25
  • 0.32
  • 0.58
  • 0.83

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.